The phenomenon of series and parallel resonance takes place in the series or parallel R-L-C circuit which leads to unity power factor. Voltage and current in R – L – C circuit are in phase with each other.
Resonance is used in many communicate circuit such as radio receiver.
Resonance in series RLC series resonance in parallel RLC anti resonance / parallel resonance.
- Condition for resonance XL = XC
- Resonant frequency (Fr): for given values of R-L-C the inductive reactance XL become exactly aqual to the capacitive reactance Xc only at one particular frequency. This frequency is called as resonant frequency and denoted by (fr)
- Expression for resonant frequency(fr): we know thet XL = 2ƛ FL – Inductive reactance
Xc = – capacitive reactance
At a particular frequency ȴ = fr, the Inductive and capacitive reactance are exactly equal
XL = XC ……at ȴ = fr
Ie L =
fr2 =
fr =
H2
And = wr =
rad/sec
Quality factor / Q factor
The quality of resonance circuit is measured in terms of efficiency of L and C to stare energy and the efficiency of L and C to store energy as measured in terms of a factor called quality factor or Q factor it is expressed as
Q = and Q =
The sharpness of tuning of R-L-C series circuit or its selectivity is measured by value of Q. as the value of Q increases, sharpness of the curve also increases and the selectivity increases https://link-slot88ku.one/
Q factor in resonance
Resonance frequency
Bandwidth in resonance (BW) = f2 = b1
and
are the frequency at which the power delivered to the resistor is reduced to 50% of the power delivered to it at resonance
these frequency are called as half power https://www.nephro-ulm.de/ frequency
Bw = fr/Q
Resonance in Parallel circuit:
When a coil is in parallel with a capacitor, as shown below. The circuit is said to be in resonance.
Resonance in RLC circuit
The resonant frequency for above circuit is fr = Hz
The current at resonance is I=
The value L/RC is known as dynamic impedance.
The current at resonance is minimum. The circuits admittance must be at its minimum and one of the characteristics of a parallel resonance circuit is that admittance is very low limiting the circuits current. Unlike the series resonance circuit, the resistor in a parallel resonance circuit has a damping effect on the circuit bandwidth making the circuit less selective.
Also, since the circuit current is constant for any value of impedance, Z, the voltage across a parallel resonance circuit will have the same shape as the total impedance and for a parallel circuit the voltage waveform is generally taken from across the capacitor.
Bandwidth and selectivity:
and
are the frequency at which the power delivered to the resistor is reduced to 50% of the power https://www.ccit.tg/job-offers delivered to it at resonance
these frequency are called as half power frequency
Bw = fr/Q
Q = =
fCR = R
Resonant Frequency:
The resonant frequency for parallel resonant circuit is given as
fR=
Where L= inductance of the coil
C = is the capacitance
Rs = Resistive value of coil.
Previous year solved questions on the topic
1) A coil takes a current of 6A when connected to 24V dc supply. To obtain the same current with 50HZ ac, the voltage required was 30V. Calculate inductance and p.f of coil?
Sol: The coil will offer only resistance to dc voltage and impedance to ac voltage
R =24/6 = 4ohm
Z= 30/6 = 5ohm
XL =
= 3ohm
cosφ = = 4/5 = 0.8 lagging
2) The potential difference measured across a coil is 4.5V, when it carries a dc current of 8A. The same coil when carries ac current of 8A at 25Hz, the potential difference is 24V. Find current and power when supplied by 50V,50Hz supply?
Sol: R=V/I= 4.5/8 = 0.56ohm
At 25Hz, Z= V/I=24/8 =3ohms
XL =
= 2.93ohm
XL = 2fL = 2
x 25x L = 2.93
L=0.0187ohm
At 50Hz
XL = 2×3 =6ohm
Z = = 5.97ohm
I= 50/5.97 = 8.37A
Power = I2R = 39.28W
3) A coil having inductance of 50mH an resistance 10ohmis connected in series with a 25F capacitor across a 200V ac supply. Calculate resonant frequency and current flowing at resonance?
Sol: f0= = 142.3Hz
I0 = V/R = 200/10 = 20A
Que) A 15mH inductor is in series with a parallel combination of 80ohm resistor and 20F capacitor. If the angular frequency of the applied voltage is 1000rad/s find admittance?
Sol: XL = 2fL = 1000x15x10-3 = 15ohm
XL = 1/C = 50ohm
Impedance of parallel combination Z = 80||-j50 = 22.5-j36
Total impedance = j15+22.5-j36 = 22.5-j21
Admittance Y= 1/Z = 0.023-j0.022 siemens
- Access more from QB here
Test your knowledge with some MCQ on the topic
- The current flowing through an insulating medium is called
- Conduction
- Convection
- Radiation
- None
- In a parallel circuit, we consider _____________ instead of impedance.
- Resistance
- Capacitance
- Inductance
- None
You can attempt more here: MCQ Test link
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