{"id":8949,"date":"2025-12-06T00:44:47","date_gmt":"2025-12-05T19:14:47","guid":{"rendered":"https:\/\/www.goseeko.com\/blog\/?p=8949"},"modified":"2026-04-26T22:26:36","modified_gmt":"2026-04-26T16:56:36","slug":"electric-field-intensity","status":"publish","type":"post","link":"https:\/\/www.goseeko.com\/blog\/electric-field-intensity\/","title":{"rendered":"Electric Field Intensity"},"content":{"rendered":"\n<p>Consider a point charge Q1 as shown in figure:<\/p>\n\n\n\n\n\n<p>If any other similar charge Q2 is brought near it Q2 experiences a force. Infact if Q2 is moved around Q1 still Q2 experiences a force as shown in figure.<\/p>\n\n\n\n<p>Thus, there exists a region around a charge in which it exerts force on any other charge. This region where a particular charge exerts a force on any other charge located in that region called <a href=\"https:\/\/en.wikipedia.org\/wiki\/Electric_field\">electric field<\/a> of that charge. The electric field of Q1 is shown in figure (b).<\/p>\n\n\n\n<p>The force experienced by the charge Q2 due to Q1 is given by Coulombs law as ,<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"19\" height=\"27\" src=\"\">&nbsp;= Q1 Q2 \/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">R<sup>2<\/sup> 12&nbsp; . <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"28\" src=\"\"><\/p>\n\n\n\n<p>Thus, force per unit charge can be written as:<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"26\" height=\"27\" src=\"\">&nbsp;\/Q2 = Q1 \/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">R<sup>2<\/sup> 12&nbsp; . <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"28\" src=\"\"><\/p>\n\n\n\n<p>This force exerted per unit charge is called electric field intensity or electric field strength. It is a vector quantity and is directed along a segment from the charge Q1 to the position of any other charge.<p><span style=\"color: #ffffff;\"><a style=\"color: #ffffff;\" title=\"toto slot\" href=\"https:\/\/library.ulab.edu.bd\/\">toto slot<\/a><\/span><\/p><\/p>\n\n\n\n<p>It is denoted as <img loading=\"lazy\" decoding=\"async\" width=\"12\" height=\"27\" src=\"\">.<\/p>\n\n\n\n<p>Another definition of electric field is the force experienced by a unit positive test charge that is Q2 = 1C.<\/p>\n\n\n\n<p>Consider a charge Q1 as shown in figure below. The unit positive charge Q2=1C is placed at distance R from Q1. Then the force acting on Q2 due to Q1 is along the unit vector <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">&nbsp;As the charge Q2 is unit charge the force exerted on Q2 is nothing but electric field intensity &nbsp;<img loading=\"lazy\" decoding=\"async\" width=\"15\" height=\"27\" src=\"\">of Q1. Then the force acting on Q2 due to Q1 is along the unit vector <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">As the charge Q2 is unit charge the force exerted onQ2 is nothing but electric field intensity <img loading=\"lazy\" decoding=\"async\" width=\"12\" height=\"27\" src=\"\">of Q1 at a point where unit charge is placed.<\/p>\n\n\n\n\n\n<p>Concept of electric field intensity<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"12\" height=\"27\" src=\"\">&nbsp;= Q1 \/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">R<sup>2&nbsp; <\/sup>&nbsp;<img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\"><\/p>\n\n\n\n<p>If a charge Q1 is located at the centre of the spherical coordinate system then unit vector <img loading=\"lazy\" decoding=\"async\" width=\"30\" height=\"20\" src=\"\">in equation (3) becomes the radial unit vector <img loading=\"lazy\" decoding=\"async\" width=\"30\" height=\"20\" src=\"\">coming radially outwards from Q1 and the distance R is the radius of the sphere r.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Electric field due to point charges<\/strong><\/h2>\n\n\n\n<p>Consider n charges Q1,Q2,\u2026\u2026..Qn as shown in figure . The combined electric field intensity is to be obtained at point P. The distances of point P from Q1,Q2\u2026\u2026Qn are R1,R2,R3\u2026\u2026\u2026Rn. The unit vectors along these directions are <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">1, <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">2, <img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">3\u2026\u2026<img loading=\"lazy\" decoding=\"async\" width=\"27\" height=\"20\" src=\"\">n.<\/p>\n\n\n\n\n\n<p>Then the total electric field intensity at point P is the vector sum of the individual field intensities produced by various charges at the point P<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"15\" height=\"27\" src=\"\">&nbsp;= <img loading=\"lazy\" decoding=\"async\" width=\"24\" height=\"27\" src=\"\">&nbsp;+ <img loading=\"lazy\" decoding=\"async\" width=\"24\" height=\"27\" src=\"\">&nbsp;+ <img loading=\"lazy\" decoding=\"async\" width=\"40\" height=\"27\" src=\"\">&nbsp;\u2026\u2026\u2026\u2026\u2026\u2026\u2026. + <img loading=\"lazy\" decoding=\"async\" width=\"25\" height=\"27\" src=\"\"><\/p>\n\n\n\n<p>= Q1\/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">R<sup>2&nbsp; <\/sup>. <img loading=\"lazy\" decoding=\"async\" width=\"32\" height=\"28\" src=\"\">&nbsp;&nbsp;&nbsp; + Q2\/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">R<sup>2&nbsp; <\/sup>. <img loading=\"lazy\" decoding=\"async\" width=\"32\" height=\"28\" src=\"\">&nbsp; + \u2026\u2026\u2026\u2026\u2026+ Qn\/4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"23\" height=\"20\" src=\"\">Rn<sup>2&nbsp; <\/sup>. <img loading=\"lazy\" decoding=\"async\" width=\"32\" height=\"28\" src=\"\"><\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"32\" height=\"27\" src=\"\">1\/ 4 \u03c0 <img loading=\"lazy\" decoding=\"async\" width=\"82\" height=\"20\" src=\"\">\/ Ri <sup>2&nbsp; <\/sup><img loading=\"lazy\" decoding=\"async\" width=\"29\" height=\"28\" src=\"\"><\/p>\n\n\n\n<p>Each unit vector can be obtained by using the method discussed earlier<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"29\" height=\"28\" src=\"\">&nbsp;= <img loading=\"lazy\" decoding=\"async\" width=\"17\" height=\"31\" src=\"\">&nbsp; &#8211; <img loading=\"lazy\" decoding=\"async\" width=\"13\" height=\"28\" src=\"\">&nbsp; \/ | <img loading=\"lazy\" decoding=\"async\" width=\"17\" height=\"31\" src=\"\">&nbsp; &#8211; <img loading=\"lazy\" decoding=\"async\" width=\"13\" height=\"28\" src=\"\">&nbsp; |<\/p>\n\n\n\n<p>Where <img loading=\"lazy\" decoding=\"async\" width=\"17\" height=\"31\" src=\"\">&nbsp;= Position vector of point P<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <img loading=\"lazy\" decoding=\"async\" width=\"13\" height=\"28\" src=\"\">&nbsp;= Position vector of point where charge Q1 is placed.<\/p>\n\n\n\n<p>Determine the field intensity at P(-0.2,0,0,-2.3) m due to a point charge of +5nC at Q(0.2,0.1,-2.5)m in air.  <a href=\"https:\/\/ichc2026.org\/\">https:\/\/ichc2026.org\/<\/a><\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n<p>Substituting value of <img loading=\"lazy\" decoding=\"async\" width=\"17\" height=\"20\" src=\"\">,<\/p>\n\n\n\n\n\n<p>This is electric field intensity at point P.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Consider a point charge Q1 as shown in figure: If any other similar charge Q2 is brought near it Q2 experiences a&hellip;<\/p>\n","protected":false},"author":28,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[1],"tags":[],"class_list":["post-8949","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.3.1 - 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