{"id":7875,"date":"2022-04-29T11:28:01","date_gmt":"2022-04-29T05:58:01","guid":{"rendered":"https:\/\/www.goseeko.com\/blog\/?p=7875"},"modified":"2025-06-02T20:47:08","modified_gmt":"2025-06-02T15:17:08","slug":"what-are-the-definite-and-indefinite-integrals-explained-with-examples","status":"publish","type":"post","link":"https:\/\/www.goseeko.com\/blog\/what-are-the-definite-and-indefinite-integrals-explained-with-examples\/","title":{"rendered":"What are the definite and indefinite integrals? Explained with examples"},"content":{"rendered":"\n<p>In calculus, the definite and indefinite integrals are the types of integration that we use to integrate the functions. The function can be exponential, power, logarithmic, constant, polynomial, or linear. We use these types of integral to determine the area under the curve.<\/p>\n\n\n\n<p>The limits of calculus are also used to define the integral. In this post, we will learn the definition and formulas of the definite and indefinite integrals along with a lot of examples.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>What are definite and indefinite integrals?<\/strong><\/h2>\n\n\n\n<p>The<a href=\"https:\/\/brilliant.org\/wiki\/definite-integrals\/\" target=\"_blank\" rel=\"noreferrer noopener\"> definite integral<\/a> is a type of integral in which the upper and the lower limits are applied to integrate the functions. In this type of integral, the interval of initial and final terms of a graph are used. The interval (u, v) is also known as the boundaries of the function.<\/p>\n\n\n\n<p>The equation used to define the definite integral is given below.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/PQPru2WRz-1Mwz-J_8TbufFc7h4eTVvRNuzgIXk1-efMI6BuiekqXFXD1Tpz60AuRdkRzr_JAUKbOtBM6KunYkvD2dKH83fP4z9HKVhwB5-OOq_nyeLLoawKOhVhvYaHCiVGJgq3\" alt=\"\" style=\"width:196px;height:38px\"\/><\/figure>\n\n\n\n<p><strong>\u00b7 &nbsp; &nbsp; &nbsp; In<\/strong><\/p>\n\n\n\n<p><strong><img loading=\"lazy\" decoding=\"async\" width=\"46\" height=\"31\" src=\"https:\/\/lh6.googleusercontent.com\/wBAl8qnwG4ET3ij8jKvgwTVhUwv33q_7atQFfcCeYXy7vse5GGYj9IFgT_d9HAgxGgKjeFHhF0vW5EbXnjtVCIdXk-JFHaV2FDBRhSoIZmYm-XjNDDWVyCoazUc6NoSPIoWKfwzB\"><\/strong><\/p>\n\n\n\n<p>\u00a0 and v are the lower and upper boundaries respectively and it is known as the integral notation of definite integral.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 f(y) is the integrand function.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 dy is the variable of integral.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 F(b) \u2013 F(a) is the fundamental rule of calculus to apply the boundaries.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 M is the numerical value of the definite integral.<\/p>\n\n\n\n<p>On the other hand, the indefinite integral is the other type of integral used to find the volume and area under the graph. In this type of integral, the upper and the lower limits are not applied. The simple integral notation is used in the indefinite integral.<\/p>\n\n\n\n<p>\u0283 f(y) dy = F(y) + C<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 \u00a0\u0283 it is the integral notation.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 f(y) is the integrand function.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 dy is the variable of integration.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 F(y) is the result of the function after integrating the function.<\/p>\n\n\n\n<p>\u00b7 \u00a0 \u00a0 \u00a0 C is the integral constant.<\/p>\n\n\n\n<p>These types of integral are frequently used to find the area, volume, and central points.\u00a0<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Rules of integration<\/strong><\/h2>\n\n\n\n<p>Below are some well-known rules of integral.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td><strong>Rule name<\/strong><\/td><td><strong>Rules<\/strong><\/td><\/tr><tr><td>The sum rule<\/td><td>\u0283 (f(y) + g(y)) dy = \u0283 f(y) dy + \u0283 g(y) dy<\/td><\/tr><tr><td>The constant rule<\/td><td>\u0283 C dy = Cy, where c is any constant<\/td><\/tr><tr><td>The difference rule<\/td><td>\u0283 (f(y) &#8211; g(y)) dy = \u0283 f(y) dy &#8211; \u0283 g(y) dy<\/td><\/tr><tr><td>The constant function rule<\/td><td>\u0283 (f(y) dy = C \u0283 (f(y) dy<\/td><\/tr><tr><td>The power rule<\/td><td>\u0283 [(f(y)]<sup>n<\/sup> = [f(y)]<sup>n+1<\/sup> \/ n + 1<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>How to calculate the definite and indefinite integral?<\/strong><\/h2>\n\n\n\n<p>By using the rules of integration, the problems of the definite and indefinite integral can be solved easily. Below are some examples of these types of integral.<\/p>\n\n\n\n<p><strong>Example 1: For the definite integral<\/strong><\/p>\n\n\n\n<p><strong>Integrate 5x<\/strong><strong><sup>3<\/sup><\/strong><strong> + 12sin(x) \u2013 5x<\/strong><strong><sup>2<\/sup><\/strong><strong>y<\/strong><strong><sup>5<\/sup><\/strong><strong> + 11x<\/strong><strong><sup>2<\/sup><\/strong><strong> + 5 with respect to x have boundary values [1, 4].<\/strong><\/p>\n\n\n\n<p><strong>Solution<\/strong><\/p>\n\n\n\n<p>Step 1: Use the integral notation of the definite integral and write the given function along with the variable of integration.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/XuBxZQmmACozy4MSXDWcXrS40-FgZaolR6n3bKI8T1v3IGaXjIdmPx5rqgn4pui7ncyYQ1ONMoRV0aLH00ZolSoYPBJDU-ruQo-NDu75obsfOBoFSVTJhFAFfuNn6bM16J5xKizu\" alt=\"\" style=\"width:271px;height:37px\"\/><\/figure>\n\n\n\n<p>Step 2: Now use the sum rule and the difference rule of integral and apply the definite integral notation separately to each term.\u00a0<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/WDzRanpvokjg-gHDyp89MQVObH_-1xK5VifCZLELYhu7ZpHQk0uB7OdNBx0mpLQ0jR45jAe4HOuP4k9TIID74aUMxfIkKFOe7JSe8dyA-mSQsjw6fvmG1f1vjNqMe_SFgyfUasyK\" alt=\"\" style=\"width:590px;height:56px\"\/><\/figure>\n\n\n\n<p>Step 3: Use the constant and constant function rule of integral on the above expression.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/AFZbS26DzbUSn_Qm3NpI_FkFEls7_2SzCdXQy0QUPJq574m6Y_lNLpoXmWJ1_3eNjFwVDon7iA6Wku4wUyG_lWaWAr2GP7Sv4ZzXuUVf-XHeA4UiYKSgKveLnYDNkY24gCzaLC3k\" alt=\"\" style=\"width:612px;height:125px\"\/><\/figure>\n\n\n\n<p>Step 4: Now integrate the above expression by using the power and trigonometric rules of integral.\u00a0<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/MbvQaXw6wAwhaz4Ou4NgmYd6CA9K895crC4sSbjTkqLU0Ldds5JUHTJ5K1s2soKLcNZPIX-OThYziXw7Ca_NgCqtsZwmN4HIM--t7gHF6wSN5l8TqncMW9cW7g3dV48o7ecMjZlc\" alt=\"\" style=\"width:633px;height:150px\"\/><\/figure>\n\n\n\n<p>Step 5: Use the fundamental theorem of calculus <img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/p31jKFimlPJrMarPWDAhPnmtYCpC27M00qyUcFKmakyhqja6wzVBQoEjDd74r3XhJdrMJH192rlJYLSWGS3c2oX5Mpk9fhkY0gi4x1Q7GW1s4UUS68Ha4KIcRtk74Zzbi7oULYCj\" style=\"width: 130px\">\u2019<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/6N0CLkiYnVbbZJszql2d_yoduiLfnqywassmvupZngBeTYSlGNKE72e38SlrOEOijwdZLQ8gnbImuk_Y_ZyrYq1jSpOYYXLA5N16whZs-IHQ0jqB5TA0-EgfOXMkimW-47iZ3p9Os7LCCQ5Bkw\" alt=\"\" style=\"width:593px;height:268px\"\/><\/figure>\n\n\n\n<p>To avoid such a large number of steps to get the result, you can simply use an<a href=\"https:\/\/www.meracalculator.com\/math\/integral.php\"> integral calculator<\/a>. Follow the below step to integrate the function with the steps.<\/p>\n\n\n\n<p><strong>Step 1:<\/strong> Select the type of integral i.e., definite or indefinite.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/FSS44w6dQyshhHonfQy2shBXR6-ff2-9nYcJNa3kttZtqQkjWwA2O379RiFGLpxTvm7rU8nuRy52h0txfjdZ3T4eZeLEe4_MOfmSpVTfguPJrQ33sWtvoMXbXVJFFMGCGtfFYkc6\" alt=\"\" style=\"width:664px;height:190px\"\/><\/figure>\n\n\n\n<p><strong>Step 2:<\/strong> Input the integrand.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/GYdkLz8Pw7d0d429sdpTJSSxwvkKn5d6H5l7ogBvYndJU5FysgUd4ntPSFi6ix54vyaQSnKsbLqLcqQ9QEuErSdoovZKEZFHTuRhWDvkSSAzD32ge_ECgt9JHWXcDkdg5ZHLvs4Z\" alt=\"\" style=\"width:631px;height:197px\"\/><\/figure>\n\n\n\n<p><strong>Step 3:<\/strong> choose the integrating variable.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/76UopoXbb3YDwyiwT7MqtXRR267Bi9e2hXxRXtucOyoWGRV1JcbbJzSIl1cUkoWx1FD9jDd7Cbfsh0snMWbeiE2Uux01AsRYe0UOwpRhpqxOp1XGxL6_E1TraBwMb0ttXMVvSvjr\" alt=\"\" style=\"width:661px;height:228px\"\/><\/figure>\n\n\n\n<p><strong>Step 4:<\/strong> Enter the upper and lower limit in case of the definite integral.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/aYAh9miMm-6Shm2FNhk5z3mR3vI5TbgYgat3Fe-58prOdOv8dpnCTs1ERliWfHt_hkPQYvQ0gAyYR9L0TUQ5CbfYMeUqA2yDWLCqxkZQbbjJu0kdvtQGYz9eRGp_VEg2hpaM2YXW\" alt=\"\" style=\"width:585px;height:193px\"\/><\/figure>\n\n\n\n<p><strong>Step 5:<\/strong> Press the calculate button to get the result.<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"624\" height=\"105\" src=\"https:\/\/lh5.googleusercontent.com\/xiWF9X-XXlddeoVrjPDcl16OU_vZKEidO9yVajIkLQ4xU5tRH-UbdGdmkJQi6BoZLqyOnWww04lFbruR0epcTto9ejsiTJFEfE8iM0CdP7cMkp1rhTI1u9hwtvlT02akNyPh7BqN\"><\/p>\n\n\n\n<p><strong>Step 6:<\/strong> The solution with steps will show below the calculate button.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/tAA43Pe69_bHjxiXNb5A7JSZFQYxSyiHSVFqb6KpAXdel0cQh8PguEUeB8FpO_HYjKheWpH3hmWgFOLAWoGwd--jvzL8CkZ9LFSmkUREe80Ol-zX-TzGzubd8HEtkk3Yaz634s90\" alt=\"\" style=\"width:606px;height:221px\"\/><\/figure>\n\n\n\n<p><strong>Example 2: For indefinite integral<\/strong><\/p>\n\n\n\n<p>I<strong>ntegrate x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x with respect to x.<\/strong><\/p>\n\n\n\n<p><strong>Solution<\/strong><\/p>\n\n\n\n<p><strong>Step 1:<\/strong> Use the integral notation of the indefinite integral and write the given function along with the variable of integration.<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx<\/p>\n\n\n\n<p><strong>Step 2:<\/strong> Now use the sum rule and the difference rule of integral and apply the indefinite integral notation separately to each term.<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx = \u0283 (x<sup>5<\/sup>) dx &#8211; \u0283 sin(x) dx \u2013 \u0283 5y<sup>5<\/sup> dx + \u0283 13x<sup>3<\/sup> dx &#8211; \u0283 5x dx<\/p>\n\n\n\n<p><strong>Step 3:<\/strong> Use the constant and constant function rule of integral on the above expression.&nbsp;<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx = \u0283 (x<sup>5<\/sup>) dx &#8211; \u0283 sin(x) dx \u2013 5y<sup>5<\/sup> \u0283 dx + 13\u0283 x<sup>3<\/sup> dx &#8211; 5\u0283 x dx<\/p>\n\n\n\n<p><strong>Step 4:<\/strong> Now integrate the above expression by using the power and trigonometric rules of integral.<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx = x<sup>5+1 <\/sup>\/ 5 + 1 &#8211; (-cos(x)) \u2013 5y<sup>5<\/sup> (x) + 13 (x<sup>3+1<\/sup> \/ 3 + 1) &#8211; 5 (x<sup>1+1<\/sup><sub> <\/sub>\/ 1 + 1) + C<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx = x<sup>6 <\/sup>\/ 6 &#8211; (-cos(x)) \u2013 5y<sup>5<\/sup> (x) + 13 (x<sup>4<\/sup> \/ 4) &#8211; 5 (x<sup>2<\/sup><sub> <\/sub>\/ 2) + C<\/p>\n\n\n\n<p>\u0283 (x<sup>5<\/sup> &#8211; sin(x) \u2013 5y<sup>5<\/sup> + 13x<sup>3<\/sup> + 5x) dx = x<sup>6<\/sup>\/6 + cos(x) \u2013 5xy<sup>5<\/sup> + 13x<sup>4<\/sup>\/4 &#8211; 5x<sup>2<\/sup>\/2 + C<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Summary<\/strong><\/h2>\n\n\n\n<p>Now you are witnessed that the types of the integral can be solved easily without any difficulty. In this post, we\u2019ve learned about the basics of the types of integrals along with examples and also learned how to solve definite and indefinite integrals using an<a href=\"https:\/\/www.antiderivativecalculator.net\/\"> antiderivative calculator<\/a>. Now you can solve any problem either by definite integral or indefinite easily.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In calculus, the definite and indefinite integrals are the types of integration used to integrate the functions. The function can be exponential, power, logarithmic, constant, polynomial, or linear. These types of integral are used frequently to determine the area under the curve.<\/p>\n","protected":false},"author":3,"featured_media":7883,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[31],"tags":[],"class_list":["post-7875","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-maths"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.3.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>What are the definite and indefinite integrals? Explained with examples - Goseeko blog<\/title>\n<meta name=\"description\" content=\"In calculus, the definite and indefinite integrals are the types of integration used to integrate the functions. The function can be exponential, power, logarithmic, constant, polynomial, or linear. 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