{"id":7132,"date":"2022-01-19T11:59:43","date_gmt":"2022-01-19T06:29:43","guid":{"rendered":"https:\/\/www.goseeko.com\/blog\/?p=7132"},"modified":"2025-12-21T10:10:32","modified_gmt":"2025-12-21T04:40:32","slug":"what-is-merge-sort","status":"publish","type":"post","link":"https:\/\/www.goseeko.com\/blog\/what-is-merge-sort\/","title":{"rendered":"What is Merge sort?"},"content":{"rendered":"\n

Merge Sort<\/a> is based on a divide and conquer strategy. It divides the unsorted list into n sublists such that each sublist contains one element. Each sublist is then sorted and merged until there is only one sublist. <\/p>\n\n\n\n

 Step1 : Divide the list into sublists such that each sublist contains only one element.<\/p>\n\n\n\n

 Step2 : Sort each sublist and Merge them.<\/p>\n\n\n\n

 Step3 : Repeat Step 2 till the entire list is sorted. <\/p>\n\n\n\n

Algorithm for Merge Sort:<\/strong><\/h2>\n\n\n\n

 Let    x = no. of elements in array A<\/p>\n\n\n\n

    y = no. of elements in array B<\/p>\n\n\n\n

    C = sorted array with no. of elements n<\/p>\n\n\n\n

    n = x+y<\/p>\n\n\n\n

Following algorithm merges a sorted x element array A and sorted y element array B into a sorted array C, with n = x + y elements. We must always keep track of the locations of the smallest element of A and the smallest element of B which have not yet been placed in C. Let LA and LB denote these locations, respectively. Also, let LC denote the location in C to be filled. Thus, initially, we set <\/p>\n\n\n\n

 LA : = 1, <\/p>\n\n\n\n

 LB : = 1 and <\/p>\n\n\n\n

 LC : = 1. <\/p>\n\n\n\n

 At each step , we compare A[LA] and B[LB] and assign the smaller element to C[LC]. <\/p>\n\n\n\n

 Then  <\/p>\n\n\n\n

 LC:= LC + 1,<\/p>\n\n\n\n

 LA: = LA + 1, if a new element has come from A . <\/p>\n\n\n\n

 LB: = LB + 1, if a new element has come from B. <\/p>\n\n\n\n

 Furthermore, if LA> x, then the remaining elements of B are assigned to C;  <\/p>\n\n\n\n

  LB >y, then the remaining https:\/\/brixtonwintercarnival.com\/media\/<\/a> elements of A are assigned to C. <\/p>\n\n\n\n

Thus the algorithm becomes<\/p>\n\n\n\n

 MERGING ( A, x, B, y, C)<\/p>\n\n\n\n

 1. [Initialize ] Set LA : = 1 , LB := 1 AND LC : = 1<\/p>\n\n\n\n

 2. [Compare] Repeat while LA <= x and LB <= y<\/p>\n\n\n\n

 If A[LA] < B[LB] , then<\/p>\n\n\n\n

 (a) [Assign element from A to C ] set C[LC] = A[LA]<\/p>\n\n\n\n

 (b) [Update pointers ] Set LC := LC +1 and LA = LA+1<\/p>\n\n\n\n

 Else<\/p>\n\n\n\n

 (a) [Assign element from B to C] Set C[LC] = B[LB]<\/p>\n\n\n\n

 (b) [Update Pointers] Set LC := LC +1 and LB = LB +1<\/p>\n\n\n\n

 [End of loop]<\/p>\n\n\n\n

 3. [Assign remaining elements to C]<\/p>\n\n\n\n

 If LA > x , then<\/p>\n\n\n\n

 Repeat for K= 0 ,1,2,……..,y\u2013LB<\/p>\n\n\n\n

 Set C[LC+K] = B[LB+K]<\/p>\n\n\n\n

 [End of loop]<\/p>\n\n\n\n

 Else<\/p>\n\n\n\n

 Repeat for K = 0,1,2,……,x\u2013LA<\/p>\n\n\n\n

 Set C[LC+K] = A[LA+K]<\/p>\n\n\n\n

 [End of loop]<\/p>\n\n\n\n

 4. Exit<\/p>\n\n\n\n

<\/p>\n\n\n\n

Interested in learning about similar topics? Here are a few hand-picked blogs for you!<\/strong><\/p>\n\n\n\n

    \n
  1. What is data structure?<\/a><\/li>\n\n\n\n
  2. Explain computer processor?<\/a><\/li>\n\n\n\n
  3. What is Memory?<\/a> https:\/\/adminpg.foreigners.bu.edu.eg\/<\/a><\/li>\n\n\n\n
  4. What is Computer?<\/a><\/li>\n<\/ol>\n\n\n\n

    <\/p>\n","protected":false},"excerpt":{"rendered":"

    It divides the unsorted list into n sublists such that each sublist contains one element. <\/p>\n","protected":false},"author":28,"featured_media":7133,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[36],"tags":[],"class_list":["post-7132","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-computer-science-software-engineering-blog"],"yoast_head":"\nWhat is Merge sort? - Goseeko blog<\/title>\n<meta name=\"description\" content=\"Merge Sort is based on a divide and conquer strategy. 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