{"id":6537,"date":"2021-09-28T12:48:50","date_gmt":"2021-09-28T07:18:50","guid":{"rendered":"https:\/\/www.goseeko.com\/blog\/?p=5737"},"modified":"2021-09-28T12:48:50","modified_gmt":"2021-09-28T07:18:50","slug":"what-is-overloading-of-function","status":"publish","type":"post","link":"https:\/\/www.goseeko.com\/blog\/what-is-overloading-of-function\/","title":{"rendered":"What is Overloading of Function?"},"content":{"rendered":"\n

The C++ programming feature of function overloading<\/a> allows us to have many functions with the same name but different argument lists. When I say parameter list, I’m referring to the data type and order in which the parameters are presented. <\/p>\n\n\n\n

The parameter list of a function myfunction(int a, double b), for example, is (int, double), which is different from the parameter list of a function myfunction(double a, int b) (double, int). Overloading is a polymorphism that happens throughout the compilation process. Let’s look at the overloading rules now that we know what a parameter list is:\u00a0<\/p>\n\n\n\n

we can have the following functions in the same scope.<\/p>\n\n\n\n

sum(int a, int b)<\/p>\n\n\n\n

sum(int a, int b, int c)<\/p>\n\n\n\n

Rules  – <\/strong><\/h2>\n\n\n\n

Three different circumstances or various parameters:<\/p>\n\n\n\n

1. The parameter types for these functions are different.<\/p>\n\n\n\n

 sum(int a, int b)<\/p>\n\n\n\n

sum(double a, double b)<\/p>\n\n\n\n

2. The number of parameters in these functions varies.<\/p>\n\n\n\n

sum(int a, int b)<\/p>\n\n\n\n

sum(int a, int b, int c)<\/p>\n\n\n\n

3. The parameters of these functions are in a different order.<\/p>\n\n\n\n

sum(int a, double b)<\/p>\n\n\n\n

sum(double a, int b)<\/p>\n\n\n\n

program <\/strong><\/h2>\n\n\n\n

#include <\/p>\n\n\n\n

using namespace std;<\/p>\n\n\n\n

class Addition {<\/p>\n\n\n\n

public:<\/p>\n\n\n\n

    int sum(int num1,int num2) {<\/p>\n\n\n\n

        return num1+num2;<\/p>\n\n\n\n

    }<\/p>\n\n\n\n

    int sum(int num1,int num2, int num3) {<\/p>\n\n\n\n

       return num1+num2+num3;<\/p>\n\n\n\n

    }<\/p>\n\n\n\n

};<\/p>\n\n\n\n

int main(void) {<\/p>\n\n\n\n

    Addition obj;<\/p>\n\n\n\n

    cout<<obj.sum(16, 19)<<endl;<\/p>\n\n\n\n

    cout<<obj.sum(18, 10, 100);<\/p>\n\n\n\n

    return 0;<\/p>\n\n\n\n

}<\/p>\n\n\n\n

Output<\/p>\n\n\n\n

35<\/p>\n\n\n\n

128<\/p>\n\n\n\n

Advantages  <\/strong><\/h2>\n\n\n\n